Ten > Quadratic Equation
x^2 - 27x + 182 = 0 | Solve by factorization method.
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Solution
The required values of x are x = {13, 14}.
Given
$\rm x^{2} - 27 x + 182 = 0$
$\rm or, x^{2} - (13 + 14) x + 182 = 0$
$\rm or, x^{2} - 13x - 14x + 182 = 0$
$\rm or, x (x - 13) - 14( x - 13) = 0$
$\rm or, (x - 14)(x - 13) = 0$
Either
$\rm (x - 14) = 0$
$\rm \therefore x = 14$
Or
$\rm (x - 13) = 0$
$\rm \therefore x = 13$
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